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131430440114003 = 1225110728139753
BaseRepresentation
bin11101111000100100001000…
…101100100001011101010011
3122020100121221100110002112102
4131320210020230201131103
5114211324020132122003
61143310151033551015
736453351554103542
oct3570441054413523
9566317840402472
10131430440114003
1138972378072728
12128a812457546b
135844ab679c124
1424653a545a159
15102dc19cbb588
hex778908b21753

131430440114003 has 4 divisors (see below), whose sum is σ = 131441168266008. Its totient is φ = 131419711962000.

The previous prime is 131430440113967. The next prime is 131430440114009. The reversal of 131430440114003 is 300411044034131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131430440114003 - 212 = 131430440109907 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131430440114009) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5364057626 + ... + 5364082127.

It is an arithmetic number, because the mean of its divisors is an integer number (32860292066502).

Almost surely, 2131430440114003 is an apocalyptic number.

131430440114003 is a deficient number, since it is larger than the sum of its proper divisors (10728152005).

131430440114003 is a wasteful number, since it uses less digits than its factorization.

131430440114003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10728152004.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 131430440114003 its reverse (300411044034131), we get a palindrome (431841484148134).

The spelling of 131430440114003 in words is "one hundred thirty-one trillion, four hundred thirty billion, four hundred forty million, one hundred fourteen thousand, three".

Divisors: 1 12251 10728139753 131430440114003