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13143089441 is a prime number
BaseRepresentation
bin11000011110110001…
…11010000100100001
31020220222001010021102
430033120322010201
5203404112330231
610012102004145
7643461263006
oct141730720441
936828033242
1013143089441
115634a27699
122669716655
131315c21301
148c97758ad
1551dcb8acb
hex30f63a121

13143089441 has 2 divisors, whose sum is σ = 13143089442. Its totient is φ = 13143089440.

The previous prime is 13143089429. The next prime is 13143089461. The reversal of 13143089441 is 14498034131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12438717841 + 704371600 = 111529^2 + 26540^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13143089441 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 13143089395 and 13143089404.

It is not a weakly prime, because it can be changed into another prime (13143089461) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6571544720 + 6571544721.

It is an arithmetic number, because the mean of its divisors is an integer number (6571544721).

Almost surely, 213143089441 is an apocalyptic number.

It is an amenable number.

13143089441 is a deficient number, since it is larger than the sum of its proper divisors (1).

13143089441 is an equidigital number, since it uses as much as digits as its factorization.

13143089441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 41472, while the sum is 38.

The spelling of 13143089441 in words is "thirteen billion, one hundred forty-three million, eighty-nine thousand, four hundred forty-one".