13143244013331 has 8 divisors (see below), whose sum is σ = 17544171702720. Its totient is φ = 8752239499752.

The previous prime is 13143244013281. The next prime is 13143244013351. The reversal of 13143244013331 is 13331044234131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13143244013331 - 2¹⁵ = 13143243980563 is a prime.

It is a super-4 number, since 4×13143244013331⁴ (a number of 54 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 13143244013292 and 13143244013301.

It is not an unprimeable number, because it can be changed into a prime (13143244013351) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2480790861 + ... + 2480796158.

It is an arithmetic number, because the mean of its divisors is an integer number (2193021462840).

Almost surely, 2^{13143244013331} is an apocalyptic number.

13143244013331 is a deficient number, since it is larger than the sum of its proper divisors (4400927689389).

13143244013331 is an equidigital number, since it uses as much as digits as its factorization.

13143244013331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4961587905.

The product of its (nonzero) digits is 31104, while the sum is 33.

Adding to 13143244013331 its reverse (13331044234131), we get a palindrome (26474288247462).

The spelling of 13143244013331 in words is "thirteen trillion, one hundred forty-three billion, two hundred forty-four million, thirteen thousand, three hundred thirty-one".