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131432444234131 is a prime number
BaseRepresentation
bin11101111000100110000000…
…001001101000100110010011
3122020100211010000112221111211
4131320212000021220212103
5114211342121210443011
61143311121545120551
736453452330615425
oct3570460011504623
9566324100487454
10131432444234131
1138973206373857
12128a85a3789157
135845045a59921
1424655156a8815
15102dcd5be4b21
hex778980268993

131432444234131 has 2 divisors, whose sum is σ = 131432444234132. Its totient is φ = 131432444234130.

The previous prime is 131432444234051. The next prime is 131432444234177.

131432444234131 is nontrivially palindromic in base 10.

It is a strong prime.

It is a palprime.

It is a cyclic number.

It is not a de Polignac number, because 131432444234131 - 213 = 131432444225939 is a prime.

It is a super-2 number, since 2×1314324442341312 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131432444234431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65716222117065 + 65716222117066.

It is an arithmetic number, because the mean of its divisors is an integer number (65716222117066).

Almost surely, 2131432444234131 is an apocalyptic number.

131432444234131 is a deficient number, since it is larger than the sum of its proper divisors (1).

131432444234131 is an equidigital number, since it uses as much as digits as its factorization.

131432444234131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 331776, while the sum is 40.

The spelling of 131432444234131 in words is "one hundred thirty-one trillion, four hundred thirty-two billion, four hundred forty-four million, two hundred thirty-four thousand, one hundred thirty-one".