Base | Representation |
---|---|
bin | 11101111000100110100001… |
… | …111011110101101110000011 |
3 | 122020100212120112002211101102 |
4 | 131320212201323311232003 |
5 | 114211344301311340303 |
6 | 1143311254113525015 |
7 | 36453502352456132 |
oct | 3570464173655603 |
9 | 566325515084342 |
10 | 131433011043203 |
11 | 38973477311901 |
12 | 128a872157376b |
13 | 5845106303ccc |
14 | 246556aa91919 |
15 | 102dd1a858288 |
hex | 7789a1ef5b83 |
131433011043203 has 4 divisors (see below), whose sum is σ = 131433263971680. Its totient is φ = 131432758114728.
The previous prime is 131433011043199. The next prime is 131433011043289. The reversal of 131433011043203 is 302340110334131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131433011043203 - 22 = 131433011043199 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131433011043403) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 125683163 + ... + 126724596.
It is an arithmetic number, because the mean of its divisors is an integer number (32858315992920).
Almost surely, 2131433011043203 is an apocalyptic number.
131433011043203 is a deficient number, since it is larger than the sum of its proper divisors (252928477).
131433011043203 is an equidigital number, since it uses as much as digits as its factorization.
131433011043203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 252928476.
The product of its (nonzero) digits is 7776, while the sum is 29.
Adding to 131433011043203 its reverse (302340110334131), we get a palindrome (433773121377334).
The spelling of 131433011043203 in words is "one hundred thirty-one trillion, four hundred thirty-three billion, eleven million, forty-three thousand, two hundred three".
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