Base | Representation |
---|---|
bin | 111101001101000000… |
… | …1011111101011100001 |
3 | 110120020210120101001111 |
4 | 1322122001133223201 |
5 | 4123133333231144 |
6 | 140213551303321 |
7 | 12332014635304 |
oct | 1723201375341 |
9 | 416223511044 |
10 | 131433102049 |
11 | 50816617997 |
12 | 2158081ab41 |
13 | c517a73202 |
14 | 650b956b3b |
15 | 3643a96534 |
hex | 1e9a05fae1 |
131433102049 has 2 divisors, whose sum is σ = 131433102050. Its totient is φ = 131433102048.
The previous prime is 131433102029. The next prime is 131433102071. The reversal of 131433102049 is 940201334131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 108520830625 + 22912271424 = 329425^2 + 151368^2 .
It is a cyclic number.
It is not a de Polignac number, because 131433102049 - 215 = 131433069281 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 131433102049.
It is not a weakly prime, because it can be changed into another prime (131433102029) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65716551024 + 65716551025.
It is an arithmetic number, because the mean of its divisors is an integer number (65716551025).
Almost surely, 2131433102049 is an apocalyptic number.
It is an amenable number.
131433102049 is a deficient number, since it is larger than the sum of its proper divisors (1).
131433102049 is an equidigital number, since it uses as much as digits as its factorization.
131433102049 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7776, while the sum is 31.
The spelling of 131433102049 in words is "one hundred thirty-one billion, four hundred thirty-three million, one hundred two thousand, forty-nine".
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