Base | Representation |
---|---|
bin | 11101111000100110111011… |
… | …100001110101000011010011 |
3 | 122020100220200110002001112202 |
4 | 131320212323201311003103 |
5 | 114211401141222313324 |
6 | 1143311404453113415 |
7 | 36453516115303403 |
oct | 3570467341650323 |
9 | 566326613061482 |
10 | 131433440432339 |
11 | 38973677730261 |
12 | 128a882132886b |
13 | 5845174265516 |
14 | 24655abb06803 |
15 | 102dd433c48ae |
hex | 7789bb8750d3 |
131433440432339 has 2 divisors, whose sum is σ = 131433440432340. Its totient is φ = 131433440432338.
The previous prime is 131433440432309. The next prime is 131433440432401. The reversal of 131433440432339 is 933234044334131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131433440432339 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131433440432293 and 131433440432302.
It is not a weakly prime, because it can be changed into another prime (131433440432309) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65716720216169 + 65716720216170.
It is an arithmetic number, because the mean of its divisors is an integer number (65716720216170).
Almost surely, 2131433440432339 is an apocalyptic number.
131433440432339 is a deficient number, since it is larger than the sum of its proper divisors (1).
131433440432339 is an equidigital number, since it uses as much as digits as its factorization.
131433440432339 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3359232, while the sum is 47.
The spelling of 131433440432339 in words is "one hundred thirty-one trillion, four hundred thirty-three billion, four hundred forty million, four hundred thirty-two thousand, three hundred thirty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •