Base | Representation |
---|---|
bin | 1011111101000010110011… |
… | …0001100001011111110011 |
3 | 1201112111021201220012121001 |
4 | 2333100230301201133303 |
5 | 3210320040340334043 |
6 | 43541545552142431 |
7 | 2524401331033552 |
oct | 277205461413763 |
9 | 51474251805531 |
10 | 13143351105523 |
11 | 4208078064031 |
12 | 1583329837a17 |
13 | 7445498b4092 |
14 | 3361da733d99 |
15 | 17bd4e6a374d |
hex | bf42cc617f3 |
13143351105523 has 2 divisors, whose sum is σ = 13143351105524. Its totient is φ = 13143351105522.
The previous prime is 13143351105487. The next prime is 13143351105581. The reversal of 13143351105523 is 32550115334131.
It is a weak prime.
It is an emirp because it is prime and its reverse (32550115334131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13143351105523 - 29 = 13143351105011 is a prime.
It is a super-2 number, since 2×131433511055232 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13143351103523) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6571675552761 + 6571675552762.
It is an arithmetic number, because the mean of its divisors is an integer number (6571675552762).
Almost surely, 213143351105523 is an apocalyptic number.
13143351105523 is a deficient number, since it is larger than the sum of its proper divisors (1).
13143351105523 is an equidigital number, since it uses as much as digits as its factorization.
13143351105523 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 81000, while the sum is 37.
Adding to 13143351105523 its reverse (32550115334131), we get a palindrome (45693466439654).
The spelling of 13143351105523 in words is "thirteen trillion, one hundred forty-three billion, three hundred fifty-one million, one hundred five thousand, five hundred twenty-three".
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