13143412335401 has 4 divisors (see below), whose sum is σ = 13143420278400. Its totient is φ = 13143404392404.

The previous prime is 13143412335353. The next prime is 13143412335467. The reversal of 13143412335401 is 10453321434131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 13143412335401 - 2⁶ = 13143412335337 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13143412334401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 446561 + ... + 5146478.

It is an arithmetic number, because the mean of its divisors is an integer number (3285855069600).

Almost surely, 2^{13143412335401} is an apocalyptic number.

It is an amenable number.

13143412335401 is a deficient number, since it is larger than the sum of its proper divisors (7942999).

13143412335401 is an equidigital number, since it uses as much as digits as its factorization.

13143412335401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7942998.

The product of its (nonzero) digits is 51840, while the sum is 35.

Adding to 13143412335401 its reverse (10453321434131), we get a palindrome (23596733769532).

The spelling of 13143412335401 in words is "thirteen trillion, one hundred forty-three billion, four hundred twelve million, three hundred thirty-five thousand, four hundred one".