13143415441433 has 4 divisors (see below), whose sum is σ = 13143423688500. Its totient is φ = 13143407194368.

The previous prime is 13143415441423. The next prime is 13143415441483. The reversal of 13143415441433 is 33414451434131.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 11612882741824 + 1530532699609 = 3407768^2 + 1237147^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13143415441433 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13143415441423) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 885308 + ... + 5202941.

It is an arithmetic number, because the mean of its divisors is an integer number (3285855922125).

Almost surely, 2^{13143415441433} is an apocalyptic number.

It is an amenable number.

13143415441433 is a deficient number, since it is larger than the sum of its proper divisors (8247067).

13143415441433 is an equidigital number, since it uses as much as digits as its factorization.

13143415441433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8247066.

The product of its digits is 414720, while the sum is 41.

Adding to 13143415441433 its reverse (33414451434131), we get a palindrome (46557866875564).

The spelling of 13143415441433 in words is "thirteen trillion, one hundred forty-three billion, four hundred fifteen million, four hundred forty-one thousand, four hundred thirty-three".