Base | Representation |
---|---|
bin | 1011111101000011000100… |
… | …0100111101100110100010 |
3 | 1201112111110202202120211220 |
4 | 2333100301010331212202 |
5 | 3210320212331411432 |
6 | 43542001051515510 |
7 | 2524403165542131 |
oct | 277206104754642 |
9 | 51474422676756 |
10 | 13143423310242 |
11 | 42081048a0555 |
12 | 1583349a58b96 |
13 | 74455b845274 |
14 | 33620616b918 |
15 | 17bd55bb772c |
hex | bf43113d9a2 |
13143423310242 has 8 divisors (see below), whose sum is σ = 26286846620496. Its totient is φ = 4381141103412.
The previous prime is 13143423310211. The next prime is 13143423310261. The reversal of 13143423310242 is 24201332434131.
13143423310242 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
13143423310242 is an admirable number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1095285275848 + ... + 1095285275859.
It is an arithmetic number, because the mean of its divisors is an integer number (3285855827562).
Almost surely, 213143423310242 is an apocalyptic number.
13143423310242 is a primitive abundant number, since it is smaller than the sum of its proper divisors, none of which is abundant.
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13143423310242 is a wasteful number, since it uses less digits than its factorization.
13143423310242 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2190570551712.
The product of its (nonzero) digits is 41472, while the sum is 33.
Adding to 13143423310242 its reverse (24201332434131), we get a palindrome (37344755744373).
The spelling of 13143423310242 in words is "thirteen trillion, one hundred forty-three billion, four hundred twenty-three million, three hundred ten thousand, two hundred forty-two".
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