Base | Representation |
---|---|
bin | 11000011110110100… |
… | …01101001110011001 |
3 | 1020220222200102111020 |
4 | 30033122031032121 |
5 | 203404204230131 |
6 | 10012113153053 |
7 | 643464212010 |
oct | 141732151631 |
9 | 36828612436 |
10 | 13143430041 |
11 | 563513a585 |
12 | 266985b789 |
13 | 1316010351 |
14 | 8c9823a77 |
15 | 51dd34996 |
hex | 30f68d399 |
13143430041 has 8 divisors (see below), whose sum is σ = 20028083904. Its totient is φ = 7510531440.
The previous prime is 13143430019. The next prime is 13143430049. The reversal of 13143430041 is 14003434131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13143430041 - 213 = 13143421849 is a prime.
It is a super-2 number, since 2×131434300412 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13143429993 and 13143430020.
It is not an unprimeable number, because it can be changed into a prime (13143430049) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 312938790 + ... + 312938831.
It is an arithmetic number, because the mean of its divisors is an integer number (2503510488).
Almost surely, 213143430041 is an apocalyptic number.
It is an amenable number.
13143430041 is a deficient number, since it is larger than the sum of its proper divisors (6884653863).
13143430041 is an equidigital number, since it uses as much as digits as its factorization.
13143430041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 625877631.
The product of its (nonzero) digits is 1728, while the sum is 24.
Adding to 13143430041 its reverse (14003434131), we get a palindrome (27146864172).
The spelling of 13143430041 in words is "thirteen billion, one hundred forty-three million, four hundred thirty thousand, forty-one".
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