1314344325201 has 4 divisors (see below), whose sum is σ = 1752459100272. Its totient is φ = 876229550132.

The previous prime is 1314344325197. The next prime is 1314344325211. The reversal of 1314344325201 is 1025234434131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1314344325201 - 2² = 1314344325197 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (1314344325211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 219057387531 + ... + 219057387536.

It is an arithmetic number, because the mean of its divisors is an integer number (438114775068).

Almost surely, 2^{1314344325201} is an apocalyptic number.

It is an amenable number.

1314344325201 is a deficient number, since it is larger than the sum of its proper divisors (438114775071).

1314344325201 is an equidigital number, since it uses as much as digits as its factorization.

1314344325201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 438114775070.

The product of its (nonzero) digits is 34560, while the sum is 33.

Adding to 1314344325201 its reverse (1025234434131), we get a palindrome (2339578759332).

The spelling of 1314344325201 in words is "one trillion, three hundred fourteen billion, three hundred forty-four million, three hundred twenty-five thousand, two hundred one".