Base | Representation |
---|---|
bin | 11101111000101000101010… |
… | …010111100011100101011011 |
3 | 122020101002111001012101222201 |
4 | 131320220222113203211123 |
5 | 114211413443300312311 |
6 | 1143312313202231031 |
7 | 36453613155406522 |
oct | 3570505227434533 |
9 | 566332431171881 |
10 | 131435300010331 |
11 | 38974441387779 |
12 | 128a9060055477 |
13 | 58453ac5b5425 |
14 | 2465706a8b4b9 |
15 | 102de0179a9c1 |
hex | 778a2a5e395b |
131435300010331 has 2 divisors, whose sum is σ = 131435300010332. Its totient is φ = 131435300010330.
The previous prime is 131435300010319. The next prime is 131435300010407. The reversal of 131435300010331 is 133010003534131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131435300010331 - 241 = 129236276754779 is a prime.
It is a super-2 number, since 2×1314353000103312 (a number of 29 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 131435300010331.
It is not a weakly prime, because it can be changed into another prime (131435300011331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65717650005165 + 65717650005166.
It is an arithmetic number, because the mean of its divisors is an integer number (65717650005166).
Almost surely, 2131435300010331 is an apocalyptic number.
131435300010331 is a deficient number, since it is larger than the sum of its proper divisors (1).
131435300010331 is an equidigital number, since it uses as much as digits as its factorization.
131435300010331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4860, while the sum is 28.
Adding to 131435300010331 its reverse (133010003534131), we get a palindrome (264445303544462).
The spelling of 131435300010331 in words is "one hundred thirty-one trillion, four hundred thirty-five billion, three hundred million, ten thousand, three hundred thirty-one".
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