Base | Representation |
---|---|
bin | 10011001000000101111… |
… | …011110111111111100011 |
3 | 11122122120222102102021201 |
4 | 103020011323313333203 |
5 | 133013302022340444 |
6 | 2443450343102031 |
7 | 163650025022146 |
oct | 23100573677743 |
9 | 4578528372251 |
10 | 1314359574499 |
11 | 467464795034 |
12 | 192894441917 |
13 | 96c3606249a |
14 | 4788870205d |
15 | 242c98d3dd4 |
hex | 13205ef7fe3 |
1314359574499 has 2 divisors, whose sum is σ = 1314359574500. Its totient is φ = 1314359574498.
The previous prime is 1314359574469. The next prime is 1314359574533. The reversal of 1314359574499 is 9944759534131.
It is a weak prime.
It is an emirp because it is prime and its reverse (9944759534131) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1314359574499 is a prime.
It is a super-2 number, since 2×13143595744992 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1314359574499.
It is not a weakly prime, because it can be changed into another prime (1314359574469) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657179787249 + 657179787250.
It is an arithmetic number, because the mean of its divisors is an integer number (657179787250).
Almost surely, 21314359574499 is an apocalyptic number.
1314359574499 is a deficient number, since it is larger than the sum of its proper divisors (1).
1314359574499 is an equidigital number, since it uses as much as digits as its factorization.
1314359574499 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 73483200, while the sum is 64.
The spelling of 1314359574499 in words is "one trillion, three hundred fourteen billion, three hundred fifty-nine million, five hundred seventy-four thousand, four hundred ninety-nine".
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