Base | Representation |
---|---|
bin | 11000011110110111… |
… | …00000100001001011 |
3 | 1020221000022202111011 |
4 | 30033123200201023 |
5 | 203404301134321 |
6 | 10012124344351 |
7 | 643500132454 |
oct | 141733404113 |
9 | 36830282434 |
10 | 13143771211 |
11 | 563535293a |
12 | 26699a50b7 |
13 | 13160cc71c |
14 | 8c98b212b |
15 | 51dda0ae1 |
hex | 30f6e084b |
13143771211 has 2 divisors, whose sum is σ = 13143771212. Its totient is φ = 13143771210.
The previous prime is 13143771191. The next prime is 13143771217. The reversal of 13143771211 is 11217734131.
It is a strong prime.
It is an emirp because it is prime and its reverse (11217734131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13143771211 - 27 = 13143771083 is a prime.
It is a super-3 number, since 3×131437712113 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (13143771217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6571885605 + 6571885606.
It is an arithmetic number, because the mean of its divisors is an integer number (6571885606).
Almost surely, 213143771211 is an apocalyptic number.
13143771211 is a deficient number, since it is larger than the sum of its proper divisors (1).
13143771211 is an equidigital number, since it uses as much as digits as its factorization.
13143771211 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3528, while the sum is 31.
The spelling of 13143771211 in words is "thirteen billion, one hundred forty-three million, seven hundred seventy-one thousand, two hundred eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •