Base | Representation |
---|---|
bin | 11000011110111010… |
… | …10110001001010011 |
3 | 1020221001020020101121 |
4 | 30033131112021103 |
5 | 203404412044021 |
6 | 10012142543111 |
7 | 643504210231 |
oct | 141735261123 |
9 | 36831206347 |
10 | 13144253011 |
11 | 563565191a |
12 | 2669b97a97 |
13 | 131623ab06 |
14 | 8c9999951 |
15 | 51de48741 |
hex | 30f756253 |
13144253011 has 8 divisors (see below), whose sum is σ = 13304091920. Its totient is φ = 12984910848.
The previous prime is 13144253009. The next prime is 13144253041. The reversal of 13144253011 is 11035244131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13144253011 - 21 = 13144253009 is a prime.
It is a super-2 number, since 2×131442530112 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13144253041) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 70806 + ... + 176923.
It is an arithmetic number, because the mean of its divisors is an integer number (1663011490).
Almost surely, 213144253011 is an apocalyptic number.
13144253011 is a deficient number, since it is larger than the sum of its proper divisors (159838909).
13144253011 is an equidigital number, since it uses as much as digits as its factorization.
13144253011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 248373.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 13144253011 its reverse (11035244131), we get a palindrome (24179497142).
The spelling of 13144253011 in words is "thirteen billion, one hundred forty-four million, two hundred fifty-three thousand, eleven".
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