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1314433 is a prime number
BaseRepresentation
bin101000000111010000001
32110210001201
411000322001
5314030213
644101201
714113111
oct5007201
92423051
101314433
1181860a
12534801
13370393
14263041
151ae6dd
hex140e81

1314433 has 2 divisors, whose sum is σ = 1314434. Its totient is φ = 1314432.

The previous prime is 1314409. The next prime is 1314437. The reversal of 1314433 is 3344131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 685584 + 628849 = 828^2 + 793^2 .

It is a cyclic number.

It is not a de Polignac number, because 1314433 - 213 = 1306241 is a prime.

It is a super-2 number, since 2×13144332 = 3455468222978, which contains 22 as substring.

1314433 is a lucky number.

It is a self number, because there is not a number n which added to its sum of digits gives 1314433.

It is not a weakly prime, because it can be changed into another prime (1314437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (7) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657216 + 657217.

It is an arithmetic number, because the mean of its divisors is an integer number (657217).

21314433 is an apocalyptic number.

It is an amenable number.

1314433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1314433 is an equidigital number, since it uses as much as digits as its factorization.

1314433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 432, while the sum is 19.

The square root of 1314433 is about 1146.4872437145. The cubic root of 1314433 is about 109.5417020397.

Adding to 1314433 its reverse (3344131), we get a palindrome (4658564).

The spelling of 1314433 in words is "one million, three hundred fourteen thousand, four hundred thirty-three".