Base | Representation |
---|---|
bin | 11000011110111011… |
… | …11100110101110011 |
3 | 1020221001112021210211 |
4 | 30033131330311303 |
5 | 203404432132012 |
6 | 10012150204551 |
7 | 643505440303 |
oct | 141735746563 |
9 | 36831467724 |
10 | 13144411507 |
11 | 563574aa07 |
12 | 266a053757 |
13 | 1316294cb6 |
14 | 8c99db603 |
15 | 51de7a6a7 |
hex | 30f77cd73 |
13144411507 has 2 divisors, whose sum is σ = 13144411508. Its totient is φ = 13144411506.
The previous prime is 13144411459. The next prime is 13144411561. The reversal of 13144411507 is 70511444131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13144411507 - 219 = 13143887219 is a prime.
It is a super-2 number, since 2×131444115072 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13144411207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6572205753 + 6572205754.
It is an arithmetic number, because the mean of its divisors is an integer number (6572205754).
Almost surely, 213144411507 is an apocalyptic number.
13144411507 is a deficient number, since it is larger than the sum of its proper divisors (1).
13144411507 is an equidigital number, since it uses as much as digits as its factorization.
13144411507 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6720, while the sum is 31.
Adding to 13144411507 its reverse (70511444131), we get a palindrome (83655855638).
The spelling of 13144411507 in words is "thirteen billion, one hundred forty-four million, four hundred eleven thousand, five hundred seven".
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