13144411534451 has 4 divisors (see below), whose sum is σ = 13146168581304. Its totient is φ = 13142654487600.

The previous prime is 13144411534447. The next prime is 13144411534469. The reversal of 13144411534451 is 15443511444131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13144411534451 - 2² = 13144411534447 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13144411534399 and 13144411534408.

It is not an unprimeable number, because it can be changed into a prime (13144414534451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 878512205 + ... + 878527166.

It is an arithmetic number, because the mean of its divisors is an integer number (3286542145326).

Almost surely, 2^{13144411534451} is an apocalyptic number.

13144411534451 is a deficient number, since it is larger than the sum of its proper divisors (1757046853).

13144411534451 is an equidigital number, since it uses as much as digits as its factorization.

13144411534451 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1757046852.

The product of its digits is 230400, while the sum is 41.

Adding to 13144411534451 its reverse (15443511444131), we get a palindrome (28587922978582).

The spelling of 13144411534451 in words is "thirteen trillion, one hundred forty-four billion, four hundred eleven million, five hundred thirty-four thousand, four hundred fifty-one".