Base | Representation |
---|---|
bin | 111101001101010111… |
… | …1000110011001101011 |
3 | 110120021122001202100022 |
4 | 1322122233012121223 |
5 | 4123144413312011 |
6 | 140215055431055 |
7 | 12332221356623 |
oct | 1723257063153 |
9 | 416248052308 |
10 | 131445057131 |
11 | 50822342a23 |
12 | 2158482548b |
13 | c51a39a91b |
14 | 650d389883 |
15 | 3644b588db |
hex | 1e9abc666b |
131445057131 has 2 divisors, whose sum is σ = 131445057132. Its totient is φ = 131445057130.
The previous prime is 131445057089. The next prime is 131445057137. The reversal of 131445057131 is 131750544131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131445057131 - 230 = 130371315307 is a prime.
It is a super-2 number, since 2×1314450571312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 131445057091 and 131445057100.
It is not a weakly prime, because it can be changed into another prime (131445057137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65722528565 + 65722528566.
It is an arithmetic number, because the mean of its divisors is an integer number (65722528566).
Almost surely, 2131445057131 is an apocalyptic number.
131445057131 is a deficient number, since it is larger than the sum of its proper divisors (1).
131445057131 is an equidigital number, since it uses as much as digits as its factorization.
131445057131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 25200, while the sum is 35.
The spelling of 131445057131 in words is "one hundred thirty-one billion, four hundred forty-five million, fifty-seven thousand, one hundred thirty-one".
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