Base | Representation |
---|---|
bin | 111101001101100100… |
… | …1101011111000100011 |
3 | 110120022010011211101111 |
4 | 1322123021223320203 |
5 | 4123203204321103 |
6 | 140215505044151 |
7 | 12332334534325 |
oct | 1723311537043 |
9 | 416263154344 |
10 | 131452026403 |
11 | 50826273055 |
12 | 21587026657 |
13 | c51b96ab59 |
14 | 6510281615 |
15 | 364558386d |
hex | 1e9b26be23 |
131452026403 has 2 divisors, whose sum is σ = 131452026404. Its totient is φ = 131452026402.
The previous prime is 131452026359. The next prime is 131452026421. The reversal of 131452026403 is 304620254131.
It is a strong prime.
It is an emirp because it is prime and its reverse (304620254131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131452026403 - 213 = 131452018211 is a prime.
It is not a weakly prime, because it can be changed into another prime (131452026463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65726013201 + 65726013202.
It is an arithmetic number, because the mean of its divisors is an integer number (65726013202).
Almost surely, 2131452026403 is an apocalyptic number.
131452026403 is a deficient number, since it is larger than the sum of its proper divisors (1).
131452026403 is an equidigital number, since it uses as much as digits as its factorization.
131452026403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17280, while the sum is 31.
The spelling of 131452026403 in words is "one hundred thirty-one billion, four hundred fifty-two million, twenty-six thousand, four hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •