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131452402442 = 265726201221
BaseRepresentation
bin111101001101100101…
…1000111101100001010
3110120022010212221012212
41322123023013230022
54123203303334232
6140215521105122
712332340661544
oct1723313075412
9416263787185
10131452402442
11508264aa629
12215871881a2
13c51ba7006a
14651033c694
153645609eb2
hex1e9b2c7b0a

131452402442 has 4 divisors (see below), whose sum is σ = 197178603666. Its totient is φ = 65726201220.

The previous prime is 131452402399. The next prime is 131452402447. The reversal of 131452402442 is 244204254131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 131443227601 + 9174841 = 362551^2 + 3029^2 .

It is a junction number, because it is equal to n+sod(n) for n = 131452402399 and 131452402408.

It is not an unprimeable number, because it can be changed into a prime (131452402447) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32863100609 + ... + 32863100612.

Almost surely, 2131452402442 is an apocalyptic number.

131452402442 is a deficient number, since it is larger than the sum of its proper divisors (65726201224).

131452402442 is an equidigital number, since it uses as much as digits as its factorization.

131452402442 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 65726201223.

The product of its (nonzero) digits is 30720, while the sum is 32.

Adding to 131452402442 its reverse (244204254131), we get a palindrome (375656656573).

The spelling of 131452402442 in words is "one hundred thirty-one billion, four hundred fifty-two million, four hundred two thousand, four hundred forty-two".

Divisors: 1 2 65726201221 131452402442