Base | Representation |
---|---|
bin | 1011111101001010110100… |
… | …0110101111011010011001 |
3 | 1201112200211210020021000021 |
4 | 2333102231012233122121 |
5 | 3210333443030314233 |
6 | 43542543343310441 |
7 | 2524505563441621 |
oct | 277225506573231 |
9 | 51480753207007 |
10 | 13145504151193 |
11 | 4208a82433117 |
12 | 158382a8ab421 |
13 | 7448009856bb |
14 | 33636266b881 |
15 | 17be286e7e2d |
hex | bf4ad1af699 |
13145504151193 has 2 divisors, whose sum is σ = 13145504151194. Its totient is φ = 13145504151192.
The previous prime is 13145504151119. The next prime is 13145504151251. The reversal of 13145504151193 is 39115140554131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11781074575449 + 1364429575744 = 3432357^2 + 1168088^2 .
It is a cyclic number.
It is not a de Polignac number, because 13145504151193 - 241 = 10946480895641 is a prime.
It is not a weakly prime, because it can be changed into another prime (13145504151113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6572752075596 + 6572752075597.
It is an arithmetic number, because the mean of its divisors is an integer number (6572752075597).
Almost surely, 213145504151193 is an apocalyptic number.
It is an amenable number.
13145504151193 is a deficient number, since it is larger than the sum of its proper divisors (1).
13145504151193 is an equidigital number, since it uses as much as digits as its factorization.
13145504151193 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162000, while the sum is 43.
The spelling of 13145504151193 in words is "thirteen trillion, one hundred forty-five billion, five hundred four million, one hundred fifty-one thousand, one hundred ninety-three".
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