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13145504151193 is a prime number
BaseRepresentation
bin1011111101001010110100…
…0110101111011010011001
31201112200211210020021000021
42333102231012233122121
53210333443030314233
643542543343310441
72524505563441621
oct277225506573231
951480753207007
1013145504151193
114208a82433117
12158382a8ab421
137448009856bb
1433636266b881
1517be286e7e2d
hexbf4ad1af699

13145504151193 has 2 divisors, whose sum is σ = 13145504151194. Its totient is φ = 13145504151192.

The previous prime is 13145504151119. The next prime is 13145504151251. The reversal of 13145504151193 is 39115140554131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11781074575449 + 1364429575744 = 3432357^2 + 1168088^2 .

It is a cyclic number.

It is not a de Polignac number, because 13145504151193 - 241 = 10946480895641 is a prime.

It is not a weakly prime, because it can be changed into another prime (13145504151113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6572752075596 + 6572752075597.

It is an arithmetic number, because the mean of its divisors is an integer number (6572752075597).

Almost surely, 213145504151193 is an apocalyptic number.

It is an amenable number.

13145504151193 is a deficient number, since it is larger than the sum of its proper divisors (1).

13145504151193 is an equidigital number, since it uses as much as digits as its factorization.

13145504151193 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162000, while the sum is 43.

The spelling of 13145504151193 in words is "thirteen trillion, one hundred forty-five billion, five hundred four million, one hundred fifty-one thousand, one hundred ninety-three".