Base | Representation |
---|---|
bin | 11101111001000011110001… |
… | …101010011111000110010011 |
3 | 122020110212122000020222212102 |
4 | 131321003301222133012103 |
5 | 114212403104320124301 |
6 | 1143333530124151015 |
7 | 36455663501452415 |
oct | 3571036152370623 |
9 | 566425560228772 |
10 | 131464413442451 |
11 | 38985821133181 |
12 | 128b282609846b |
13 | 584806c0a793b |
14 | 2466ca94749b5 |
15 | 102ea5764cb6b |
hex | 7790f1a9f193 |
131464413442451 has 2 divisors, whose sum is σ = 131464413442452. Its totient is φ = 131464413442450.
The previous prime is 131464413442433. The next prime is 131464413442457. The reversal of 131464413442451 is 154244314464131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131464413442451 - 218 = 131464413180307 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131464413442396 and 131464413442405.
It is not a weakly prime, because it can be changed into another prime (131464413442457) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65732206721225 + 65732206721226.
It is an arithmetic number, because the mean of its divisors is an integer number (65732206721226).
Almost surely, 2131464413442451 is an apocalyptic number.
131464413442451 is a deficient number, since it is larger than the sum of its proper divisors (1).
131464413442451 is an equidigital number, since it uses as much as digits as its factorization.
131464413442451 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2211840, while the sum is 47.
The spelling of 131464413442451 in words is "one hundred thirty-one trillion, four hundred sixty-four billion, four hundred thirteen million, four hundred forty-two thousand, four hundred fifty-one".
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