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13147408137169 is a prime number
BaseRepresentation
bin1011111101010001111010…
…0101110111101111010001
31201112212202110220202202101
42333110132211313233101
53210401342440342134
643543500320320401
72524604013162265
oct277243645675721
951485673822671
1013147408137169
11420986a160a49
121584080473101
13744a45283617
143364a34920a5
1517beda941e14
hexbf51e977bd1

13147408137169 has 2 divisors, whose sum is σ = 13147408137170. Its totient is φ = 13147408137168.

The previous prime is 13147408137011. The next prime is 13147408137217. The reversal of 13147408137169 is 96173180474131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12767043610000 + 380364527169 = 3573100^2 + 616737^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13147408137169 is a prime.

It is a super-2 number, since 2×131474081371692 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13147408137769) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6573704068584 + 6573704068585.

It is an arithmetic number, because the mean of its divisors is an integer number (6573704068585).

Almost surely, 213147408137169 is an apocalyptic number.

It is an amenable number.

13147408137169 is a deficient number, since it is larger than the sum of its proper divisors (1).

13147408137169 is an equidigital number, since it uses as much as digits as its factorization.

13147408137169 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3048192, while the sum is 55.

The spelling of 13147408137169 in words is "thirteen trillion, one hundred forty-seven billion, four hundred eight million, one hundred thirty-seven thousand, one hundred sixty-nine".