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13147658131339 = 76491718872811
BaseRepresentation
bin1011111101010010110101…
…1111100001011110001011
31201112220101220022210021201
42333110231133201132023
53210402400440200324
643543541210445031
72524613140121254
oct277245537413613
951486356283251
1013147658131339
1142099882902a6
121584130133777
13744a84cc3474
143364c8769b2b
1517c002874444
hexbf52d7e178b

13147658131339 has 4 divisors (see below), whose sum is σ = 13149377011800. Its totient is φ = 13145939250880.

The previous prime is 13147658131331. The next prime is 13147658131393. The reversal of 13147658131339 is 93313185674131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13147658131339 - 23 = 13147658131331 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13147658131339.

It is not an unprimeable number, because it can be changed into a prime (13147658131331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 859428757 + ... + 859444054.

It is an arithmetic number, because the mean of its divisors is an integer number (3287344252950).

Almost surely, 213147658131339 is an apocalyptic number.

13147658131339 is a deficient number, since it is larger than the sum of its proper divisors (1718880461).

13147658131339 is an equidigital number, since it uses as much as digits as its factorization.

13147658131339 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1718880460.

The product of its digits is 4898880, while the sum is 55.

The spelling of 13147658131339 in words is "thirteen trillion, one hundred forty-seven billion, six hundred fifty-eight million, one hundred thirty-one thousand, three hundred thirty-nine".

Divisors: 1 7649 1718872811 13147658131339