Base | Representation |
---|---|
bin | 1011111101010100111101… |
… | …0111010000010010001011 |
3 | 1201112221212111121021102121 |
4 | 2333111033113100102023 |
5 | 3210410031423423011 |
6 | 43544113430312111 |
7 | 2524633210204441 |
oct | 277251727202213 |
9 | 51487774537377 |
10 | 13148226389131 |
11 | 420a14a028839 |
12 | 158426a4b8637 |
13 | 744b45957092 |
14 | 33654000cb91 |
15 | 17c0376c1e71 |
hex | bf54f5d048b |
13148226389131 has 2 divisors, whose sum is σ = 13148226389132. Its totient is φ = 13148226389130.
The previous prime is 13148226389071. The next prime is 13148226389147. The reversal of 13148226389131 is 13198362284131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13148226389131 - 241 = 10949203133579 is a prime.
It is a super-2 number, since 2×131482263891312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13148226389191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6574113194565 + 6574113194566.
It is an arithmetic number, because the mean of its divisors is an integer number (6574113194566).
Almost surely, 213148226389131 is an apocalyptic number.
13148226389131 is a deficient number, since it is larger than the sum of its proper divisors (1).
13148226389131 is an equidigital number, since it uses as much as digits as its factorization.
13148226389131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1492992, while the sum is 52.
The spelling of 13148226389131 in words is "thirteen trillion, one hundred forty-eight billion, two hundred twenty-six million, three hundred eighty-nine thousand, one hundred thirty-one".
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