Base | Representation |
---|---|
bin | 1011111101010101011101… |
… | …1101101010000110011111 |
3 | 1201112222012222022112011101 |
4 | 2333111113131222012133 |
5 | 3210410321221113341 |
6 | 43544135123133531 |
7 | 2524636450253620 |
oct | 277252735520637 |
9 | 51488188275141 |
10 | 13148362285471 |
11 | 420a209807766 |
12 | 15842a7b142a7 |
13 | 744b67b5860a |
14 | 3365540a5a47 |
15 | 17c0445b7831 |
hex | bf55776a19f |
13148362285471 has 16 divisors (see below), whose sum is σ = 15159919811904. Its totient is φ = 11170112937984.
The previous prime is 13148362285451. The next prime is 13148362285549. The reversal of 13148362285471 is 17458226384131.
It is not a de Polignac number, because 13148362285471 - 215 = 13148362252703 is a prime.
It is a super-3 number, since 3×131483622854713 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13148362285441) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 82514251 + ... + 82673443.
It is an arithmetic number, because the mean of its divisors is an integer number (947494988244).
Almost surely, 213148362285471 is an apocalyptic number.
13148362285471 is a deficient number, since it is larger than the sum of its proper divisors (2011557526433).
13148362285471 is a wasteful number, since it uses less digits than its factorization.
13148362285471 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 263730.
The product of its digits is 7741440, while the sum is 55.
The spelling of 13148362285471 in words is "thirteen trillion, one hundred forty-eight billion, three hundred sixty-two million, two hundred eighty-five thousand, four hundred seventy-one".
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