Base | Representation |
---|---|
bin | 11101111001011001010001… |
… | …001011011111010011011001 |
3 | 122020120002012022022111110221 |
4 | 131321121101023133103121 |
5 | 114213242340114003131 |
6 | 1143352304103240041 |
7 | 36460441411460254 |
oct | 3571312113372331 |
9 | 566502168274427 |
10 | 131487490766041 |
11 | 38994593735a33 |
12 | 128b71a6749021 |
13 | 584a2a919abb7 |
14 | 246805833009b |
15 | 1030458633411 |
hex | 7796512df4d9 |
131487490766041 has 2 divisors, whose sum is σ = 131487490766042. Its totient is φ = 131487490766040.
The previous prime is 131487490765957. The next prime is 131487490766057. The reversal of 131487490766041 is 140667094784131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 105638106241600 + 25849384524441 = 10278040^2 + 5084229^2 .
It is a cyclic number.
It is not a de Polignac number, because 131487490766041 - 215 = 131487490733273 is a prime.
It is not a weakly prime, because it can be changed into another prime (131487490761041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65743745383020 + 65743745383021.
It is an arithmetic number, because the mean of its divisors is an integer number (65743745383021).
Almost surely, 2131487490766041 is an apocalyptic number.
It is an amenable number.
131487490766041 is a deficient number, since it is larger than the sum of its proper divisors (1).
131487490766041 is an equidigital number, since it uses as much as digits as its factorization.
131487490766041 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24385536, while the sum is 61.
The spelling of 131487490766041 in words is "one hundred thirty-one trillion, four hundred eighty-seven billion, four hundred ninety million, seven hundred sixty-six thousand, forty-one".
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