13149438241 has 3 divisors (see below), whose sum is σ = 13149552913. Its totient is φ = 13149323570.

The previous prime is 13149438223. The next prime is 13149438283. The reversal of 13149438241 is 14283494131.

The square root of 13149438241 is 114671.

It is a perfect power (a square), and thus also a powerful number.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 14283494131 = 19 ⋅751762849.

It is not a de Polignac number, because 13149438241 - 2⁵ = 13149438209 is a prime.

It is a Smith number, since the sum of its digits (40) coincides with the sum of the digits of its prime factors.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13149438194 and 13149438203.

It is not an unprimeable number, because it can be changed into a prime (13149408241) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 2 ways as a sum of consecutive naturals, for example, 57336 + ... + 172006.

Almost surely, 2^13149438241 is an apocalyptic number.

13149438241 is the 114671-st square number.

13149438241 is the 57336-th centered octagonal number.

It is an amenable number.

13149438241 is a deficient number, since it is larger than the sum of its proper divisors (114672).

13149438241 is an frugal number, since it uses more digits than its factorization.

13149438241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 229342 (or 114671 counting only the distinct ones).

The product of its digits is 82944, while the sum is 40.

The spelling of 13149438241 in words is "thirteen billion, one hundred forty-nine million, four hundred thirty-eight thousand, two hundred forty-one".