131501151441353 has 4 divisors (see below), whose sum is σ = 132288583486080. Its totient is φ = 130713719396628.

The previous prime is 131501151441349. The next prime is 131501151441463. The reversal of 131501151441353 is 353144151105131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131501151441353 - 2² = 131501151441349 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131501151441053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 393716022113 + ... + 393716022446.

It is an arithmetic number, because the mean of its divisors is an integer number (33072145871520).

Almost surely, 2^{131501151441353} is an apocalyptic number.

It is an amenable number.

131501151441353 is a deficient number, since it is larger than the sum of its proper divisors (787432044727).

131501151441353 is an equidigital number, since it uses as much as digits as its factorization.

131501151441353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 787432044726.

The product of its (nonzero) digits is 54000, while the sum is 38.

The spelling of 131501151441353 in words is "one hundred thirty-one trillion, five hundred one billion, one hundred fifty-one million, four hundred forty-one thousand, three hundred fifty-three".