Base | Representation |
---|---|
bin | 111101001111001000… |
… | …0001000000011100011 |
3 | 110120102202001201021121 |
4 | 1322132100020003203 |
5 | 4123310013440212 |
6 | 140225004033111 |
7 | 12333535644004 |
oct | 1723620100343 |
9 | 416382051247 |
10 | 131504046307 |
11 | 50852673407 |
12 | 215a0532797 |
13 | c52968276a |
14 | 65171431ab |
15 | 3649e0bd07 |
hex | 1e9e4080e3 |
131504046307 has 4 divisors (see below), whose sum is σ = 131505665616. Its totient is φ = 131502427000.
The previous prime is 131504046269. The next prime is 131504046367. The reversal of 131504046307 is 703640405131.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 703640405131 = 631 ⋅1115119501.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131504046307 is a prime.
It is a super-2 number, since 2×1315040463072 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131504046367) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 681028 + ... + 852529.
It is an arithmetic number, because the mean of its divisors is an integer number (32876416404).
Almost surely, 2131504046307 is an apocalyptic number.
131504046307 is a deficient number, since it is larger than the sum of its proper divisors (1619309).
131504046307 is an equidigital number, since it uses as much as digits as its factorization.
131504046307 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1619308.
The product of its (nonzero) digits is 30240, while the sum is 34.
The spelling of 131504046307 in words is "one hundred thirty-one billion, five hundred four million, forty-six thousand, three hundred seven".
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