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13150427340652 = 227469658119309
BaseRepresentation
bin1011111101011101001010…
…0011001101111101101100
31201120011112220002012022121
42333113102203031331230
53210424033344400102
643545120052322324
72525041564035640
oct277272243157554
951504486065277
1013150427340652
114210079448238
1215847836133a4
1374510692c864
143366ac456c20
1517c115a2ab37
hexbf5d28cdf6c

13150427340652 has 12 divisors (see below), whose sum is σ = 26300854681360. Its totient is φ = 5635897431696.

The previous prime is 13150427340637. The next prime is 13150427340671. The reversal of 13150427340652 is 25604372405131.

13150427340652 is an admirable number.

It is a junction number, because it is equal to n+sod(n) for n = 13150427340599 and 13150427340608.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 234829059627 + ... + 234829059682.

Almost surely, 213150427340652 is an apocalyptic number.

It is an amenable number.

13150427340652 is a primitive abundant number, since it is smaller than the sum of its proper divisors, none of which is abundant.

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13150427340652 is a wasteful number, since it uses less digits than its factorization.

13150427340652 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 469658119320 (or 469658119318 counting only the distinct ones).

The product of its (nonzero) digits is 604800, while the sum is 43.

Adding to 13150427340652 its reverse (25604372405131), we get a palindrome (38754799745783).

The spelling of 13150427340652 in words is "thirteen trillion, one hundred fifty billion, four hundred twenty-seven million, three hundred forty thousand, six hundred fifty-two".

Divisors: 1 2 4 7 14 28 469658119309 939316238618 1878632477236 3287606835163 6575213670326 13150427340652