Search a number
-
+
13150999572457 is a prime number
BaseRepresentation
bin1011111101011111010010…
…1010000110111111101001
31201120020000202211120210011
42333113310222012333221
53210431221342304312
643545252533251521
72525062012653145
oct277276452067751
951506022746704
1013150999572457
11421034245a48a
121584903193ba1
13745198355266
14336724452225
1517c14adb0da7
hexbf5f4a86fe9

13150999572457 has 2 divisors, whose sum is σ = 13150999572458. Its totient is φ = 13150999572456.

The previous prime is 13150999572421. The next prime is 13150999572481. The reversal of 13150999572457 is 75427599905131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9379126751296 + 3771872821161 = 3062536^2 + 1942131^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13150999572457 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13150999572392 and 13150999572401.

It is not a weakly prime, because it can be changed into another prime (13150999572157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6575499786228 + 6575499786229.

It is an arithmetic number, because the mean of its divisors is an integer number (6575499786229).

Almost surely, 213150999572457 is an apocalyptic number.

It is an amenable number.

13150999572457 is a deficient number, since it is larger than the sum of its proper divisors (1).

13150999572457 is an equidigital number, since it uses as much as digits as its factorization.

13150999572457 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 107163000, while the sum is 67.

The spelling of 13150999572457 in words is "thirteen trillion, one hundred fifty billion, nine hundred ninety-nine million, five hundred seventy-two thousand, four hundred fifty-seven".