Base | Representation |
---|---|
bin | 10011001000110010101… |
… | …001111110001111110001 |
3 | 11122201112021012200100101 |
4 | 103020302221332033301 |
5 | 133021321110344431 |
6 | 2444053024152401 |
7 | 164004435223366 |
oct | 23106251761761 |
9 | 4581467180311 |
10 | 1315109856241 |
11 | 46780a257895 |
12 | 192a63768701 |
13 | 9702562828c |
14 | 4791a20846d |
15 | 243206d9961 |
hex | 13232a7e3f1 |
1315109856241 has 2 divisors, whose sum is σ = 1315109856242. Its totient is φ = 1315109856240.
The previous prime is 1315109856233. The next prime is 1315109856289. The reversal of 1315109856241 is 1426589015131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1182525753600 + 132584102641 = 1087440^2 + 364121^2 .
It is a cyclic number.
It is not a de Polignac number, because 1315109856241 - 23 = 1315109856233 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1315109856191 and 1315109856200.
It is not a weakly prime, because it can be changed into another prime (1315109856041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657554928120 + 657554928121.
It is an arithmetic number, because the mean of its divisors is an integer number (657554928121).
Almost surely, 21315109856241 is an apocalyptic number.
It is an amenable number.
1315109856241 is a deficient number, since it is larger than the sum of its proper divisors (1).
1315109856241 is an equidigital number, since it uses as much as digits as its factorization.
1315109856241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 259200, while the sum is 46.
The spelling of 1315109856241 in words is "one trillion, three hundred fifteen billion, one hundred nine million, eight hundred fifty-six thousand, two hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •