Base | Representation |
---|---|
bin | 11000011111110011… |
… | …00110110111100011 |
3 | 1020221120011121222112 |
4 | 30033321212313203 |
5 | 203413311132124 |
6 | 10013005425535 |
7 | 643624164362 |
oct | 141771466743 |
9 | 36846147875 |
10 | 13151661539 |
11 | 5639851a75 |
12 | 267056b2ab |
13 | 1317932c63 |
14 | 8ca9677d9 |
15 | 51e90d90e |
hex | 30fe66de3 |
13151661539 has 2 divisors, whose sum is σ = 13151661540. Its totient is φ = 13151661538.
The previous prime is 13151661493. The next prime is 13151661563. The reversal of 13151661539 is 93516615131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13151661539 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13151661496 and 13151661505.
It is not a weakly prime, because it can be changed into another prime (13151661569) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6575830769 + 6575830770.
It is an arithmetic number, because the mean of its divisors is an integer number (6575830770).
Almost surely, 213151661539 is an apocalyptic number.
13151661539 is a deficient number, since it is larger than the sum of its proper divisors (1).
13151661539 is an equidigital number, since it uses as much as digits as its factorization.
13151661539 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 72900, while the sum is 41.
The spelling of 13151661539 in words is "thirteen billion, one hundred fifty-one million, six hundred sixty-one thousand, five hundred thirty-nine".
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