Base | Representation |
---|---|
bin | 1011111101100011111011… |
… | …0101110100010000111011 |
3 | 1201120100020111201221200121 |
4 | 2333120332311310100323 |
5 | 3210441244000433301 |
6 | 43550020233114111 |
7 | 2525134604515042 |
oct | 277307665642073 |
9 | 51510214657617 |
10 | 13152244155451 |
11 | 4210920a47075 |
12 | 1584babb58937 |
13 | 7453361592bb |
14 | 336801869559 |
15 | 17c1c02a63a1 |
hex | bf63ed7443b |
13152244155451 has 2 divisors, whose sum is σ = 13152244155452. Its totient is φ = 13152244155450.
The previous prime is 13152244155443. The next prime is 13152244155467. The reversal of 13152244155451 is 15455144225131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13152244155451 - 23 = 13152244155443 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13152244155398 and 13152244155407.
It is not a weakly prime, because it can be changed into another prime (13152244156451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6576122077725 + 6576122077726.
It is an arithmetic number, because the mean of its divisors is an integer number (6576122077726).
Almost surely, 213152244155451 is an apocalyptic number.
13152244155451 is a deficient number, since it is larger than the sum of its proper divisors (1).
13152244155451 is an equidigital number, since it uses as much as digits as its factorization.
13152244155451 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 480000, while the sum is 43.
The spelling of 13152244155451 in words is "thirteen trillion, one hundred fifty-two billion, two hundred forty-four million, one hundred fifty-five thousand, four hundred fifty-one".
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