Base | Representation |
---|---|
bin | 1011111101100100001000… |
… | …1011110001011000000011 |
3 | 1201120100101102021110120022 |
4 | 2333121002023301120003 |
5 | 3210441402330224220 |
6 | 43550025555204055 |
7 | 2525136155323664 |
oct | 277310213613003 |
9 | 51510342243508 |
10 | 13152300242435 |
11 | 421094a675052 |
12 | 15850068a662b |
13 | 745344966173 |
14 | 3368090a936b |
15 | 17c1c5184925 |
hex | bf6422f1603 |
13152300242435 has 16 divisors (see below), whose sum is σ = 15794724316800. Its totient is φ = 10513865045376.
The previous prime is 13152300242429. The next prime is 13152300242449. The reversal of 13152300242435 is 53424200325131.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13152300242435 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13152300242395 and 13152300242404.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 153481781 + ... + 153567449.
It is an arithmetic number, because the mean of its divisors is an integer number (987170269800).
Almost surely, 213152300242435 is an apocalyptic number.
13152300242435 is a deficient number, since it is larger than the sum of its proper divisors (2642424074365).
13152300242435 is a wasteful number, since it uses less digits than its factorization.
13152300242435 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 108590.
The product of its (nonzero) digits is 86400, while the sum is 35.
Adding to 13152300242435 its reverse (53424200325131), we get a palindrome (66576500567566).
The spelling of 13152300242435 in words is "thirteen trillion, one hundred fifty-two billion, three hundred million, two hundred forty-two thousand, four hundred thirty-five".
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