Base | Representation |
---|---|
bin | 10011001000111010100… |
… | …011101011101100101011 |
3 | 11122201212111122212200021 |
4 | 103020322203223230223 |
5 | 133022104030101011 |
6 | 2444114121421311 |
7 | 164010635103535 |
oct | 23107243535453 |
9 | 4581774585607 |
10 | 1315242425131 |
11 | 467878073858 |
12 | 192aa003a837 |
13 | 97046c330cb |
14 | 4792da76855 |
15 | 2432c174471 |
hex | 1323a8ebb2b |
1315242425131 has 4 divisors (see below), whose sum is σ = 1315252497832. Its totient is φ = 1315232352432.
The previous prime is 1315242425083. The next prime is 1315242425191.
1315242425131 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1315242425131 - 215 = 1315242392363 is a prime.
It is a super-2 number, since 2×13152424251312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1315242425191) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4837881 + ... + 5102506.
It is an arithmetic number, because the mean of its divisors is an integer number (328813124458).
Almost surely, 21315242425131 is an apocalyptic number.
1315242425131 is a deficient number, since it is larger than the sum of its proper divisors (10072701).
1315242425131 is an equidigital number, since it uses as much as digits as its factorization.
1315242425131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10072700.
The product of its digits is 28800, while the sum is 34.
The spelling of 1315242425131 in words is "one trillion, three hundred fifteen billion, two hundred forty-two million, four hundred twenty-five thousand, one hundred thirty-one".
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