Base | Representation |
---|---|
bin | 10011001000111110010… |
… | …100010111101111111011 |
3 | 11122202000220101102201211 |
4 | 103020332110113233323 |
5 | 133022221203120443 |
6 | 2444124254023551 |
7 | 164012332311130 |
oct | 23107624275773 |
9 | 4582026342654 |
10 | 1315305520123 |
11 | 4678aa748a81 |
12 | 192ab91a7bb7 |
13 | 97057024a1a |
14 | 479381bc587 |
15 | 2433298919d |
hex | 1323e517bfb |
1315305520123 has 8 divisors (see below), whose sum is σ = 1505273998592. Its totient is φ = 1125853964136.
The previous prime is 1315305520093. The next prime is 1315305520129. The reversal of 1315305520123 is 3210255035131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1315305520123 - 233 = 1306715585531 is a prime.
It is a super-2 number, since 2×13153055201232 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1315305520129) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 129225165 + ... + 129235342.
It is an arithmetic number, because the mean of its divisors is an integer number (188159249824).
Almost surely, 21315305520123 is an apocalyptic number.
1315305520123 is a deficient number, since it is larger than the sum of its proper divisors (189968478469).
1315305520123 is an equidigital number, since it uses as much as digits as its factorization.
1315305520123 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 258461241.
The product of its (nonzero) digits is 13500, while the sum is 31.
The spelling of 1315305520123 in words is "one trillion, three hundred fifteen billion, three hundred five million, five hundred twenty thousand, one hundred twenty-three".
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