Base | Representation |
---|---|
bin | 1011111101100111111111… |
… | …0000101101010001011011 |
3 | 1201120110001102020000022202 |
4 | 2333121333300231101123 |
5 | 3211001011313211011 |
6 | 43550320302040415 |
7 | 2525203601424023 |
oct | 277317760552133 |
9 | 51513042200282 |
10 | 13153333335131 |
11 | 421132a840970 |
12 | 158525487910b |
13 | 74547a9bbc12 |
14 | 3368a638ca83 |
15 | 17c235c0123b |
hex | bf67fc2d45b |
13153333335131 has 16 divisors (see below), whose sum is σ = 15117205142400. Its totient is φ = 11318555476800.
The previous prime is 13153333335089. The next prime is 13153333335157.
13153333335131 is nontrivially palindromic in base 10.
It is a de Polignac number, because none of the positive numbers 2k-13153333335131 is a prime.
It is a super-2 number, since 2×131533333351312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13153333335631) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 26627426 + ... + 27116903.
It is an arithmetic number, because the mean of its divisors is an integer number (944825321400).
Almost surely, 213153333335131 is an apocalyptic number.
13153333335131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
13153333335131 is a deficient number, since it is larger than the sum of its proper divisors (1963871807269).
13153333335131 is a wasteful number, since it uses less digits than its factorization.
13153333335131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 53745530.
The product of its digits is 164025, while the sum is 38.
The spelling of 13153333335131 in words is "thirteen trillion, one hundred fifty-three billion, three hundred thirty-three million, three hundred thirty-five thousand, one hundred thirty-one".
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