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131534142520241 is a prime number
BaseRepresentation
bin11101111010000100101101…
…110101110011101110110001
3122020201112121112211011100002
4131322010231311303232301
5114220023410441121431
61143425541220235345
736464012446030406
oct3572045565635661
9566645545734302
10131534142520241
1138a0235340139a
121290424623bb55
135851802365796
14246a4020c62ad
1510317890953cb
hex77a12dd73bb1

131534142520241 has 2 divisors, whose sum is σ = 131534142520242. Its totient is φ = 131534142520240.

The previous prime is 131534142520217. The next prime is 131534142520307. The reversal of 131534142520241 is 142025241435131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 100550836470016 + 30983306050225 = 10027504^2 + 5566265^2 .

It is a cyclic number.

It is not a de Polignac number, because 131534142520241 - 230 = 131533068778417 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131534142520195 and 131534142520204.

It is not a weakly prime, because it can be changed into another prime (131534142520141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65767071260120 + 65767071260121.

It is an arithmetic number, because the mean of its divisors is an integer number (65767071260121).

Almost surely, 2131534142520241 is an apocalyptic number.

It is an amenable number.

131534142520241 is a deficient number, since it is larger than the sum of its proper divisors (1).

131534142520241 is an equidigital number, since it uses as much as digits as its factorization.

131534142520241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 115200, while the sum is 38.

Adding to 131534142520241 its reverse (142025241435131), we get a palindrome (273559383955372).

The spelling of 131534142520241 in words is "one hundred thirty-one trillion, five hundred thirty-four billion, one hundred forty-two million, five hundred twenty thousand, two hundred forty-one".