Base | Representation |
---|---|
bin | 11101111010000100111101… |
… | …110011101111010010110011 |
3 | 122020201120022012220112102211 |
4 | 131322010331303233102303 |
5 | 114220024433031210420 |
6 | 1143430023550152551 |
7 | 36464022211054504 |
oct | 3572047563572263 |
9 | 566646265815384 |
10 | 131534410413235 |
11 | 38a02480646365 |
12 | 129042bbab2757 |
13 | 5851845a0154b |
14 | 246a4298dcbab |
15 | 10317a2860e5a |
hex | 77a13dcef4b3 |
131534410413235 has 16 divisors (see below), whose sum is σ = 160517072256480. Its totient is φ = 103443686348800.
The previous prime is 131534410413137. The next prime is 131534410413269. The reversal of 131534410413235 is 532314014435131.
It is not a de Polignac number, because 131534410413235 - 213 = 131534410405043 is a prime.
It is a super-2 number, since 2×1315344104132352 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 144450429 + ... + 145358161.
It is an arithmetic number, because the mean of its divisors is an integer number (10032317016030).
Almost surely, 2131534410413235 is an apocalyptic number.
131534410413235 is a deficient number, since it is larger than the sum of its proper divisors (28982661843245).
131534410413235 is an equidigital number, since it uses as much as digits as its factorization.
131534410413235 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1398998.
The product of its (nonzero) digits is 259200, while the sum is 40.
Adding to 131534410413235 its reverse (532314014435131), we get a palindrome (663848424848366).
The spelling of 131534410413235 in words is "one hundred thirty-one trillion, five hundred thirty-four billion, four hundred ten million, four hundred thirteen thousand, two hundred thirty-five".
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