Base | Representation |
---|---|
bin | 11000100000000001… |
… | …10000010001000001 |
3 | 1020221200200210221111 |
4 | 30100000300101001 |
5 | 203414301110131 |
6 | 10013113523321 |
7 | 643646126443 |
oct | 142000602101 |
9 | 36850623844 |
10 | 13153535041 |
11 | 563a911619 |
12 | 2671113541 |
13 | 131813a93a |
14 | 8cacd4493 |
15 | 51eb7dab1 |
hex | 310030441 |
13153535041 has 2 divisors, whose sum is σ = 13153535042. Its totient is φ = 13153535040.
The previous prime is 13153534991. The next prime is 13153535051. The reversal of 13153535041 is 14053535131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11178621441 + 1974913600 = 105729^2 + 44440^2 .
It is a cyclic number.
It is not a de Polignac number, because 13153535041 - 27 = 13153534913 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13153534994 and 13153535012.
It is not a weakly prime, because it can be changed into another prime (13153535051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6576767520 + 6576767521.
It is an arithmetic number, because the mean of its divisors is an integer number (6576767521).
Almost surely, 213153535041 is an apocalyptic number.
It is an amenable number.
13153535041 is a deficient number, since it is larger than the sum of its proper divisors (1).
13153535041 is an equidigital number, since it uses as much as digits as its factorization.
13153535041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13500, while the sum is 31.
The spelling of 13153535041 in words is "thirteen billion, one hundred fifty-three million, five hundred thirty-five thousand, forty-one".
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