Base | Representation |
---|---|
bin | 1011111101101010100101… |
… | …1010011001100001001011 |
3 | 1201120111212010010110211202 |
4 | 2333122221122121201023 |
5 | 3211003424211130443 |
6 | 43550513503414415 |
7 | 2525230115166143 |
oct | 277325132314113 |
9 | 51514763113752 |
10 | 13154032130123 |
11 | 4211659237995 |
12 | 158540a8b440b |
13 | 74555c6c8991 |
14 | 3369310d1923 |
15 | 17c2772367b8 |
hex | bf6a969984b |
13154032130123 has 2 divisors, whose sum is σ = 13154032130124. Its totient is φ = 13154032130122.
The previous prime is 13154032130101. The next prime is 13154032130171. The reversal of 13154032130123 is 32103123045131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13154032130123 - 218 = 13154031867979 is a prime.
It is a super-2 number, since 2×131540321301232 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13154032138123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6577016065061 + 6577016065062.
It is an arithmetic number, because the mean of its divisors is an integer number (6577016065062).
Almost surely, 213154032130123 is an apocalyptic number.
13154032130123 is a deficient number, since it is larger than the sum of its proper divisors (1).
13154032130123 is an equidigital number, since it uses as much as digits as its factorization.
13154032130123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6480, while the sum is 29.
Adding to 13154032130123 its reverse (32103123045131), we get a palindrome (45257155175254).
The spelling of 13154032130123 in words is "thirteen trillion, one hundred fifty-four billion, thirty-two million, one hundred thirty thousand, one hundred twenty-three".
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