Base | Representation |
---|---|
bin | 1011111101101010111111… |
… | …0111011011101100111011 |
3 | 1201120112010122212101102022 |
4 | 2333122233313123230323 |
5 | 3211004134420421124 |
6 | 43550532332225055 |
7 | 2525232601413041 |
oct | 277325767335473 |
9 | 51515118771368 |
10 | 13154140404539 |
11 | 4211704370082 |
12 | 158543b00b18b |
13 | 745578c78794 |
14 | 336941638391 |
15 | 17c2819c2c5e |
hex | bf6afddbb3b |
13154140404539 has 2 divisors, whose sum is σ = 13154140404540. Its totient is φ = 13154140404538.
The previous prime is 13154140404469. The next prime is 13154140404551. The reversal of 13154140404539 is 93540404145131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13154140404539 is a prime.
It is a Sophie Germain prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13154140404539.
It is not a weakly prime, because it can be changed into another prime (13154140404569) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6577070202269 + 6577070202270.
It is an arithmetic number, because the mean of its divisors is an integer number (6577070202270).
Almost surely, 213154140404539 is an apocalyptic number.
13154140404539 is a deficient number, since it is larger than the sum of its proper divisors (1).
13154140404539 is an equidigital number, since it uses as much as digits as its factorization.
13154140404539 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 518400, while the sum is 44.
The spelling of 13154140404539 in words is "thirteen trillion, one hundred fifty-four billion, one hundred forty million, four hundred four thousand, five hundred thirty-nine".
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