Base | Representation |
---|---|
bin | 11000100000000110… |
… | …00100000100100011 |
3 | 1020221201211120102002 |
4 | 30100003010010203 |
5 | 203414424443301 |
6 | 10013134514215 |
7 | 643654230464 |
oct | 142003040443 |
9 | 36851746362 |
10 | 13154140451 |
11 | 5640195461 |
12 | 267136596b |
13 | 13182c037a |
14 | 8cb010d6b |
15 | 51ec4d16b |
hex | 3100c4123 |
13154140451 has 2 divisors, whose sum is σ = 13154140452. Its totient is φ = 13154140450.
The previous prime is 13154140423. The next prime is 13154140487. The reversal of 13154140451 is 15404145131.
It is a weak prime.
It is an emirp because it is prime and its reverse (15404145131) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13154140451 is a prime.
It is a super-2 number, since 2×131541404512 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13154140411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6577070225 + 6577070226.
It is an arithmetic number, because the mean of its divisors is an integer number (6577070226).
Almost surely, 213154140451 is an apocalyptic number.
13154140451 is a deficient number, since it is larger than the sum of its proper divisors (1).
13154140451 is an equidigital number, since it uses as much as digits as its factorization.
13154140451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4800, while the sum is 29.
Adding to 13154140451 its reverse (15404145131), we get a palindrome (28558285582).
The spelling of 13154140451 in words is "thirteen billion, one hundred fifty-four million, one hundred forty thousand, four hundred fifty-one".
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