Base | Representation |
---|---|
bin | 10011001001000100110… |
… | …010110000110100110011 |
3 | 11122202022110210102112022 |
4 | 103021010302300310303 |
5 | 133022432010303301 |
6 | 2444143134222055 |
7 | 164015121536462 |
oct | 23110462606463 |
9 | 4582273712468 |
10 | 1315414150451 |
11 | 467955aa4605 |
12 | 192b2965492b |
13 | 9707369a81b |
14 | 479487b89d9 |
15 | 2433c295d1b |
hex | 13244cb0d33 |
1315414150451 has 2 divisors, whose sum is σ = 1315414150452. Its totient is φ = 1315414150450.
The previous prime is 1315414150447. The next prime is 1315414150511. The reversal of 1315414150451 is 1540514145131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1315414150451 - 22 = 1315414150447 is a prime.
It is not a weakly prime, because it can be changed into another prime (1315414150951) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657707075225 + 657707075226.
It is an arithmetic number, because the mean of its divisors is an integer number (657707075226).
Almost surely, 21315414150451 is an apocalyptic number.
1315414150451 is a deficient number, since it is larger than the sum of its proper divisors (1).
1315414150451 is an equidigital number, since it uses as much as digits as its factorization.
1315414150451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24000, while the sum is 35.
Adding to 1315414150451 its reverse (1540514145131), we get a palindrome (2855928295582).
The spelling of 1315414150451 in words is "one trillion, three hundred fifteen billion, four hundred fourteen million, one hundred fifty thousand, four hundred fifty-one".
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