Base | Representation |
---|---|
bin | 1011111101101011010001… |
… | …0001010101111010101011 |
3 | 1201120112022210220221102010 |
4 | 2333122310101111322223 |
5 | 3211004312330233301 |
6 | 43550543532211003 |
7 | 2525234456514432 |
oct | 277326421257253 |
9 | 51515283827363 |
10 | 13154214305451 |
11 | 4211742055a0a |
12 | 158545b909a63 |
13 | 74558b381a2b |
14 | 33694b394119 |
15 | 17c28821e5d6 |
hex | bf6b4455eab |
13154214305451 has 4 divisors (see below), whose sum is σ = 17538952407272. Its totient is φ = 8769476203632.
The previous prime is 13154214305447. The next prime is 13154214305549. The reversal of 13154214305451 is 15450341245131.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 13154214305451 - 22 = 13154214305447 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13154214305251) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2192369050906 + ... + 2192369050911.
It is an arithmetic number, because the mean of its divisors is an integer number (4384738101818).
Almost surely, 213154214305451 is an apocalyptic number.
13154214305451 is a deficient number, since it is larger than the sum of its proper divisors (4384738101821).
13154214305451 is an equidigital number, since it uses as much as digits as its factorization.
13154214305451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4384738101820.
The product of its (nonzero) digits is 144000, while the sum is 39.
The spelling of 13154214305451 in words is "thirteen trillion, one hundred fifty-four billion, two hundred fourteen million, three hundred five thousand, four hundred fifty-one".
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